GATE 2005 Previous Year Paper Solution Question 5 – Network & Transport Layer 03

In this video you will get to know the answer of question which was asked in the exam of GATE 2005.

Question :- On a TCP connection, current congestion window size is Congestion Window = 4 KB. The window size advertised by the receiver is Advertise Window = 6 KB. the last byte send by the sender is LastByteSent = 10240 and the last byte acknowledged by the the receiver is LastByteAcked = 8192. The current window size at the sender is :

A. 2048 bytes

B. 4096 bytes

C. 6144 bytes

D. 8192 bytes

Solution is given in the video.